sunglow genetics question

if i breed sunglow to albino do i get all albino and sunglow or do i get some normals in there somewhere


question #2 if i breed sunglow to sunglow do i get albinos, sunglows, and super sunglows
or is supersunglow impossible
this is a delema i will be facing this breeding season and need to clarify the possiblilities in order to make breeding decisions
thanks for the help anyone
Eric

Originally Posted by ericfire

if i breed sunglow to albino do i get all albino and sunglow or do i get some normals in there somewhere


question #2 if i breed sunglow to sunglow do i get albinos, sunglows, and super sunglows
or is supersunglow impossible
this is a delema i will be facing this breeding season and need to clarify the possiblilities in order to make breeding decisions
thanks for the help anyone
Eric

#1 No, you will not get any normals when breeding a Sunglow to an Albino.

#2 You are correct and a Supersunglow is an albino Supersalmon(or Superhypo if you prefer), so it is possible.

Alex is correct.
A sunglow is an albino also. Albino x albino = lots of albinos. But not really recommended.

The other combo also would be an albino x albino breeding, they just both have the hypo gene as well. It would produce all sunglows, (in theory) with some being super or double dose.

If the sunglows that you are breeding are not supers, then you will have 25% albino and 75% sunglow. The sunglows will then be 33% possible supers. If one of the breeders is a super then all will be sunglows and 50% possible super.
AlbinoXsunglow will produce 50/50. If the sunglow is a super (super hypo) then all will be sunglows. Good luck!

I understood Salmon to Salmon = ALL Salmon, +/- half Homozygous. Maybe you are correct though.

It would work the same as a het albino x het albino, only the hets are visual.
Say, for instance, H=hypo and N= normal. HN x HN would give 25% HH, 50% HN, and 25% NN. If one was a super then all would be hypo and half would be supers.

I gotta take an aspirin now, lol.

Yup, sounds about right. Don't know what I wasn't thinking

Originally Posted by heathn

It would work the same as a het albino x het albino, only the hets are visual.
Say, for instance, H=hypo and N= normal. HN x HN would give 25% HH, 50% HN, and 25% NN. If one was a super then all would be hypo and half would be supers.

I gotta take an aspirin now, lol.

I dont think thats quite how it works. Hypomelanism is a co-dominant gene. If you had hypo x hypo you would end up with ALL hypo with 50%(ish) being SUPER (dominant) hypos. No normals.

If you hypo x normal you'd end up with 50%(ish) hypos, 50% normals

So for the original question of sunglow x albino. The albino gene is recessive. But since bothe parents are homozygous (visual) for albino you will have all albinos 50% of with will be sunglows.

None of this is exact by he way and the actual results can vary.

By the way albino x albino breeding is not a real good idea. Its been known to produce defects.

Forgot the other question.

Breeding sunglow x sunglow will give you ALL sunglows, 50% of with will be super (dominant).

And by the way Rich, you had it right.

actually i beleive using the sqares you would get a quarter normal from hypo to hypo

--- H -- N

H - HH HN

N - HN NN
because normal hypos have a normal gene in them then there is a quarter chance of getting a normal with each snake ,50 percent chance normal hypo and a quarter super