Common boa genetics help

Hi! I have a 66% het anery het albino male boa I want to breed to my triple het moonglow boa. I'm still really dicey with the genetics and am taking a class this fall semester on genetics so I'll hopefully understand this a lot more. What offspring would they produce?

I would imagine possible snows (anery+albino), possible moonglows (since hypo can be passed on from a single parent), possibly ghost (hypo+anery), sunglow a (hypo+albino), albino, and lots of hets (non-visuals).

It all depends on if the anery proves out. If you get a ghost, a snow, or a moonglow it will be proved.

Also you could get hypos with a het gene as well.

Awesome! Thanks for the help!

No problem. Sorry I can't give you % outcomes. I'm still learning that myself.

Is there any way to know if the anery will prove out? His parents are an albino and an anery. He looks anery up until the end of his tail and then the color comes in.

If one of the parents was an anery, he isn't a 66% het (he IS het anery).

Awesome! I thought that would be the case but the guy was selling his friend's offspring. He probably didn't know any better.

I thought anery was recessive like albino. Are you saying its co-dominant like hypomelanism?

Originally Posted by Sanguine84

I thought anery was recessive like albino. Are you saying its co-dominant like hypomelanism?

Not at all - 66% hets are the product of het x het pairings. If the pairing WAS albino x anery, the snake is a double het.
Breeding the double het to the triple het moonglow could yield:
Possible double hets, hypo possible double hets, albino poss het anery, sunglow poss het anery, anery poss het albino, ghost poss het albino, snow, & moonglow.

That is, naturally, assuming that the pairing really was albino x anery. If the snake is actually het albino, 66% het anery - as was originally posted - none of the anery related morphs will happen unless he proves.