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piebold and a normal

stupidclauton said:
o really? i thought at best they would be 50% piebald
Click to expand...

The piebald parent is homozygous for pied and therefore has no other gene at that loci to contribute to the offspring so they will all get the piebald gene. Since the normal parent has no pied gene at all, the offspring cannot display the trait, but all will be het.
Percentages only come into play when neither parent is homzygous but one or both are het.
 
The gender would make no difference....if either parent is a homozygous (visual) piebald, bred to a normal, the offspring will inherit half of its genes from its mother, and half from its father, meaning it will inherit the piebald gene from one, whichever one it may be. So, it has a 100% chance of carrying the piebald gene, therefore 100% heterozygous. It will not show the piebald color, however, because it must be homozygous to be a visual piebald.
 
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