As Shaun said, it depends on what she was bred with. Since you state you aren't really up on genetics, here's a quickie explanation of how things work with albinism. (without some of the technical mumbo jumbo)
Albinism is a simple recessive trait. What this means to you, as a prospective breeder or buyer, is that both parents must possess the necessary genetic component(s) in order for any babies to be albino. If one parent is an albino, and the other is normal, none of the babies will be albino...but they will all carry the needed gene(s). Since they are normal looking, but carry the albino gene, they are known as heterozygous for albinism...aka het albino.
A quick breakdown of what would be expected from a couple different pairings:
1) albino x albino = all babies albino
2) albino x normal = all babies het albino (normal looking)
3) albino x het albino = half babies albino, half babies het albino (approx)
4) het alb x het alb = 1/4 babies albino, 1/2 babies het, 1/4 normal (approx)
5) het alb x normal = half of babies het albino, half normal
bottom line is that a snake is either het albino or it isn't. the %het numbers are confusing to some people, but all that number represents is the statistical possibility that the snake is carrying the gene. For example (refer to #s above):
2) all babies are het albino...these are 100% hets
3) since the normal babies are all het albino, they are 100% hets
4) eliminate the albinos from the mix. of the remaining normal looking babies, about 2/3 of them should be het albino. 2/3 = 66%, so they are 66% het
5) half (50%) of the babies will be hets, so 50% het
In reality, it is possible to get no albinos from a het to het breeding - especially with a very small litter (just ask some of the ball python people). Since these numbers are statistics, you will likely see variances in the numbers...but over a large sample size, they should be pretty close.
