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Hypo het albino x Albino = ??

B

Boa4u

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Does it mean that out of 20 babies:

5 sunglows
5 albinos
5 hypo het albino
5 normall het albino

From what I understand, an albino x het albino yields:

50% albinos
50% hets

Then if half of the albinos were also hypo, then half of your total albinos would be sunglow?

So for this analysis do you apply the recessive first and then the co-dominant as I have done above or am I looking at this totally wrong?
 
Statistically speaking, yes, that is what you would get. In the real world, however, you don't know which 50% of the litter will be hypos...you could, theoretically, end up with all your hypos being het albino, all your hypos being albino (sunglows), or getting a nice mix.
 
so is that

....... H------Na
------*------*
a......Ha-----Na or aa
------*------*
a......Ha-----Na or Na


it so confusing
 
Boa4u said:
So for this analysis do you apply the recessive first and then the co-dominant as I have done above or am I looking at this totally wrong?
Click to expand...
I don't think that it matters much which trait you apply first, nor do I think that you are looking at it totally wrong...the only "error" is trying to make a more or less linear translation of a statistical concept to an extremely limited quantity (how's that for a fancy BS answer, lol). Seriously, though, the basic concepts are correct as you outlined them. Albino x het albino will yield albinos and het albinos...about 50% of each in any given quantity. Hypo x normal will yield hypos and normals...about 50% of each in any given quantity. SO, as you implied, a hypo het albino x albino should yield
25% albino
25% het albino
25% hypo albino (sunglow)
25% hypo het albino
With a statistically significant sample size, you would likely see numbers close to this; however a single litter (even a big one) is not statistically significant, so one must be prepared to see somewhat different results based on the rules of nature. Yes, half of the babies will be albinos, and half will be hets...that is a given. The hypomelanism will be distributed randomly to half the babies, without regard for other traits. That is a simple fact which can cause huge disappointment to those that overlook it. Look on the bright side - even if the karma gods are frowning on you & you don't get a single sunglow...you''ll have a litter composed of albinos and DH sunglows:>poke2<:
 
Thank's for the info Harald, you are jarring my vague memory of my college statistics class. And yes, I will be hoping that the dice roll in my favor and that the sun will glow upon my albinos!(all pun intended!)

As for you Mr. Eric, I agree that it can get pretty confusing. At first glance, your punnet square jargon looks like it could be that song that you hear at football games when the winning team's fans start singing " ha na na na, ha na na na, hey hey, goodbye! But seriously, as far as punnets go, the only site that I have found so far that has a fair amount of punnet square info relating to snakes is on Ralph Davis Reptiles under " The Matrix ". If no one else here can letter it out for you, then if you haven't already, you might want to check out Ralph's site and see if it helps you.
 
thanks for the info and the shot too
lol
im definately in the learning stages of genetics
thanks ill check out that site
Eric
 
This problem involves two independent mutant genes. This is really too complex a problem for easy explanation in a forum. I'll just note that the original poster's answer was correct, and it does not matter which mutant is done first. The result is the same either way.

I find the Ralph Davis site very difficult to read because of all the dots. YMMV. From what I have seen of it, it's far from perfect.

I generally recommend getting a genetics text for learning genetics. Schaum's Introduction to Genetics, by Elrod and Stansfield, is as good as any and cheaper than most. Used copies are less than $10. The amount of confusing, misleading, and downright wrong genetics information on the web is truly scary.
 
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