Question about morphs.

[_Lucian_]

Im still fairly new to reptile morphs, so theres a few things I get confused over. I understand the basics, but I thought of something that left me wondering...

Lets say you have a Blizzard that is Het for Patternless.. Its morph, and what it is Het for would be simple recessive.

However, this confuses me. How is it that you can even get this? Both traits are recessive, so what makes it a blizzard? Is blizzard simply a little more dominant than Patternless? Is it completely random as to which trait will be more dominant? And when using a punnet square, is there any way to figure out what the offspring will be since they are both recessive genes?

Thanks.

 

[lilgreenbee]

It's a blizzard because it has two copies, aka homozygous, for the gene for blizzard. It would be het patternless because it only has one copy of the gene for patternless. For a simple recessive morph, you need two copies of a gene to make it visual.

How to do a Punnett Square

 

[_Lucian_]

It's a blizzard because it has two copies, aka homozygous, for the gene for blizzard. It would be het patternless because it only has one copy of the gene for patternless. For a simple recessive morph, you need two copies of a gene to make it visual.

How to do a Punnett Square

I know the basics as I said, but can a punnet square have more than 4 boxes? Apologies if that's explained in the link, I'm currently at work

 

[_Lucian_]

It's a blizzard because it has two copies, aka homozygous, for the gene for blizzard. It would be het patternless because it only has one copy of the gene for patternless. For a simple recessive morph, you need two copies of a gene to make it visual.

How to do a Punnett Square

For example, could an outcome be MMmm if they had multiple hets

 

[_Lucian_]

It's a blizzard because it has two copies, aka homozygous, for the gene for blizzard. It would be het patternless because it only has one copy of the gene for patternless. For a simple recessive morph, you need two copies of a gene to make it visual.

How to do a Punnett Square

A better example... My gecko, according to the breeder is Murphy's patternless, get for tremper. Both of those being recessive, would it be represented like mmt on the punnet square with an extra column?

 

[Dbz4246]

I will try to answer your question the best I can, I will be using ball python morphs in my example.

Pied is recessive, so is albino. So if you breed the 2 together, you will have an entire clutch of non visuals. All of the clutch will be 100% double het Albino/Pied.

Breed those babies together, and eventually a Visual Albino Pied will happen

Now breed the Albino Pied to a Pied. Since both parents are pieds, all the offspring will be Pieds, and since one parent is also Albino but not the other, All offspring will also be 100% het albino. So the entire Clutch will be Pied 100% het Albino.

This example can be used with any simple recessive morph, from any species. And to answer your other question. No, one recessive is not more Dominant than the other. It all depends on what the parents were. Hope this helps

 

[_Lucian_]

I will try to answer your question the best I can, I will be using ball python morphs in my example.

Pied is recessive, so is albino. So if you breed the 2 together, you will have an entire clutch of non visuals. All of the clutch will be 100% double het Albino/Pied.

Breed those babies together, and eventually a Visual Albino Pied will happen

Now breed the Albino Pied to a Pied. Since both parents are pieds, all the offspring will be Pieds, and since one parent is also Albino but not the other, All offspring will also be 100% het albino. So the entire Clutch will be Pied 100% het Albino.

This example can be used with any simple recessive morph, from any species. And to answer your other question. No, one recessive is not more Dominant than the other. It all depends on what the parents were. Hope this helps

That is actually the simplest, and best answer I've gotten. Thanks!. So Ill throw down another example. If I throw together a Tangerine, mixed with a MP that is het for Tangerine, Im gonna get 50% Normal het for both MP and Tangerine, and 50% Tangerine Het for MP?

 

[Dbz4246]

That is correct

 

[_Lucian_]

That is correct

Thank you. I need help on one though if you will. Lets say mom is Tremper het eclipse/blizzard and dad is MP het tremper... What would the outcome be? Thats a lot of genetics and it's real confusing. So an explanation on how to figure that one out would be great.

 

[_Lucian_]

That is correct

If I got it right, I think it would be 50% tremper, pos het mp, eclipse, blizzard, and 50% normal, pos het tremper, mp, eclipse, blizzard.

 

[Dbz4246]

Your best bet is to find a genetics calculator for the species and Morphs your looking at. The reason I used Ball pythons Morphs in my example is because that is all I know lol. The Morphs your listing I know are leopard geckos, but I have no idea what they are lol. But all genetics are essentially the same.

 

[_Lucian_]

Your best bet is to find a genetics calculator for the species and Morphs your looking at. The reason I used Ball pythons Morphs in my example is because that is all I know lol. The Morphs your listing I know are leopard geckos, but I have no idea what they are lol. But all genetics are essentially the same.

Yea I know. I drew up a square, and realized that was a tad off. The normals should be 100% her mp and tremper, 50% blizzard and eclipse... That is assuming I understand it correctly. Thank you for all the help though

Sent from my A521L using Tapatalk

 

[Dbz4246]

This is the true outcome:

Half of the offspring is Tremper 50%het Eclipse 50%het blizzard 100%Het pattern less
The other half is 50%het Eclipse 50%het Blizzard 100%Het Tremper 100%Het patternless

There you go. Is it confusing, yes lol. Good luck with all your breedings.