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sharp and kahl question

E

ericfire

T.O.T.L.E boas
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what would you get if you take a sharp albino and cross it with a kahl albino
do you get normals 100% het for both or do you get albino's het for both
:confused:
please someone enlighten me to this fact
Eric
 
could someone break down why either way
we need a genetisist ,then i could be really lost lol :ack2:
 
I believe it is two different genes at work, which is why they are incompatible. What I would like to see is a boa homozygous(sp?) for both.
 
I recall reading something about this some time ago and even though I have a fair understanding of genetics I still have only the most minimal grasp of the workings on this one. It appears that both are true amelanistic but something like one is T+ and one is T- or something along those lines. The same thing comes up in ball pythons if I understand it right (take the normal amelanistic albino and the caramel albino for instance.)

While both are exhibiting a form of amelanism (lack of melanin that is the producer of black pigment) the key in the genetic chain is appearing at different locations or something. Anyway, this produces a T+ (T = tyronnaise) or a T- albino situation. Since these are albino expressions are exactly the same, only different, mixing the 2 will produce the odd, yet completely understandable "normal" appearing offspring which in theory should be heterozygous for both traits.

I believe that an attempt has been made in the past, at least with ball pythons, to breed het offspring back but don't know what the outcome of the experiment was. I don't place any known breedings of het for incompatible strains of albinism in boas though my research these past couple of years has been lax at best. It's my current line of thought that you would could get a mixed litter of both T+ and T- but because the trait shows up on different alleles in the DNA chain that you would be hard pressed to prove that an albino boa was homozygous for both strains unless the animal(s) showed some remarkable visual cue.
 
The Kahl and Sharp albinos are two different genes located on different loci. Brian Sharp bred his strain to a Kahl many years ago and proved they were separate strains by producing all normals. When bred together you simply get dbl hets. On many of my other post I've gone into extreme detail explaining genetics 101 so I won't repeat it here.

Tyrosinase is a enzyme required to synthesize melanin (black pigment.) It is not know if the Kahl or Sharp lack black pigment because of a lack of tyrosinase (T-) or some other factor....there are a lot of ways a snake can be albino....but I won't bore you with the chemistry.
 
Hi Mark,

I was wondering about your opinion on wheather Sharp strain is T+, or not?? I find it kind of odd that it is somewhat compatable with the supposed Carmel(T+) or "Boawoman Hypo", but doesn't really look T+. any insight??
 
heathn said:
What I would like to see is a boa homozygous(sp?) for both.
Click to expand...
I think I remember someone doing this but there was a lot of problems. I think the babies were still born and had deformities like one eyes or something. I could be wrong here...its been a long time since I read this.
 
floridaboy85 said:
Hi Mark,

I was wondering about your opinion on wheather Sharp strain is T+, or not?? I find it kind of odd that it is somewhat compatable with the supposed Carmel(T+) or "Boawoman Hypo", but doesn't really look T+. any insight??
Click to expand...
Hi Andrew
I've got no idea :shrug01:
The Sharps have never been tested for functioning Tyrosinase.

Those Paradigms are interesting....but I don't know enough about them to have any opinions.
 
Hi! I THINK what happens is enzymes are kind of a chain reaction thing, one enzyme catalyzes the next. For example:

Enzyme 1 -> Enzyme 2 -> enzyme 3 -> melanin.

Say one strain doesn't produce enzyme 1 and the other doesn't produce enzyme 3. Each parent passes on one copy of each chromosome (half their genetic makeup). The babies will have one allele (copy of a gene) that does not produce enzyme 1, but will recieve a functioning allele from the other parent. Likewise, they will recieve one allele that does not produce enzyme 3, but recieve the functioning allele from the
other parent. So in theory they should be het for both. It is probably more complicated than this, but hope this helps! :)
 
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